16x^2+76x-116=0

Solution for 16x^2+76x-116=0 equation:

16x^2+76x-116=0

a = 16; b = 76; c = -116;
Δ = b2-4ac
Δ = 762-4·16·(-116)
Δ = 13200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{13200}=\sqrt{400*33}=\sqrt{400}*\sqrt{33}=20\sqrt{33}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-20\sqrt{33}}{2*16}=\frac{-76-20\sqrt{33}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+20\sqrt{33}}{2*16}=\frac{-76+20\sqrt{33}}{32}
$